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| Thread: Studying - Take a look. |  This thread is pages long: 1 2 · «PREV |
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TheRealDeal
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posted November 18, 2004 05:47 PM |
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Heres the first task, i have this do to tomorrow, and i have the biggest headache known to mankind. first of all i need someone to translate this from danish to english... then i need help with the questions. It's physics.
1: Bestem rumfanget af 2,5 kg glycerol
2: Hvor stor er temperaturstigningen, når jens tilfører varmen 8,9 kj til 65 ml glycerol ved stuetemperatur
3: Hvor meget varme skal helle tilføre et blylod for at opvarme det fra 15 grader til 90 grader, idet loddets masse er 500 g
4: viggo hælder cirka et halvt glas cola fra køleskabet(120 g, 3 grader celsius) i et halvt glas cola fra stuen (100g, 20 grader) og rører rundt. bestem fælles temperaturen
5: afstanden til månen kan ved fra jorden at sende laserlys mod en reflektor på månen. reflektionen reflektere laserlyset og sender det tilbage til jorden. Laserlys har en fart på 3*10^8 m/s, og det tager lyset 2,56 sec at nå til månen og tilbage.
6: Marianne cykler på sin nye cyek og speedometret viser 28 km/h. Marianne bremser op, hvorved farten ændres fra 28 km/h til 13,5 km/h i løbet af 6 sec. Beregn cyklens acceleration.
7: søren står på hænder, sørens masse er 60 kg, og håndfladernes samlede areal er på 120 cm^2. Beregn sørens tryk mod gulvet.
8: en dejlig varm sommerdag er temperaturen 26 grader. Den relative luftfugtighed er 35 %. bestem det faktiske indhold af vanddamp pr.m^3
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*We all know the that Foobum is the class of all that is Cake.
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Conan
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posted November 18, 2004 08:10 PM |
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I'm good with chemistry, biology and especially math.
The problem with you question is that it's in a language I don't understand!! 
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Your life as it has been is over. From this time forward, you will service.... us. - Star Trek TNG
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Svarog
Honorable
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statue-loving necrophiliac
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posted November 19, 2004 01:40 AM |
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Either translate it urself, or ask some of the danes to translate it. I cant help you otherway.
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The meek shall inherit the earth, but NOT its mineral rights.
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terje_the_ma...
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Disciple of Herodotus
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posted November 19, 2004 10:58 AM |
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Quote:
This is great! It's nice that people actually wants to help with this idea. Thanks.
This is actually very nice, people from the community, wanting to help without getting anything return(except for a heartfelt thanks)
I think it's more of a case of people wanna brag about what they're good at 
Btw, if you need help with any European history, or political science (also some philosophy and economics, but not very advanced; 1st year university at most...) IM me...
Danish is practically just very conservative Norwegian (or vice versa...  ), so I'll try to translate Real_deals questions (I haven't had chemistry or physics in 3 years, so bear over with me if the translations isn't too good...):
1. Find the volume of 2,5 kg glycerol.
2. How large is the temperature rise when James adds 8,9 kj to the heat to 65 ml at room temperature?
3. How much heat shall Helle add to a lead weight to heat it from 15 degrees C to 90 degrees C, when the mass of the weight is 500g?
4. Viggo pours ca. half a glas of Coke from the refridgerator (120g, 3 degrees C) into half a glas of Coke from the livingroom (100g, 20degrees C) and stirs. Find the common temperature.
5. The distance from the Moon to Earth can be measured by sending a "laser light" at a reflector on the Moon. The reflector reflects (sic!) and sends it back to Earth (wow, how many pleonasms!  ). Laser lights has a velocity of 3*10^8 m/s, and it takes the light 2,56 s to reach the Moon and get back. How long is the distnace from Earth to the Moon?
6. Mary rides her new bike, and its speedometre shows 28 km/h. Mary brakes down, and the velocity changes from 28 km/h to 13,5 km/h in 6 s. Estimate the acceleration of the bike.
7. Paul stands on his hands, his mass is 60 kg, and the total area of his palms are 120cm^2. Estimate Paul's pressure on the floor.
8. A lovely warm summers day, the temperature is 26 degrees C. The relative air moisture is 35%. Estimate how much "water steam" each m^3 contains.
I hope that was a good translation...
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"Sometimes I think everyone's just pretending to be brave, and none of us really are. Maybe pretending to be brave is how you get brave, I don't know."
- Grenn, A Storm of Swords.
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Mitzah
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of the Horadrim
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posted November 19, 2004 11:14 AM |
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I'm not that good at physics...I don't really get what you're trying to say either..
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terje_the_ma...
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Supreme Hero
Disciple of Herodotus
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posted November 19, 2004 11:34 AM |
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I have a vague idea, but I don't think I would have been able to solve ny of these problems...
I used to be good at it though. Nearly got an A in Chemistry, Biology and Physics in the Norwegian equivalent of 1st year Senior High School...
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"Sometimes I think everyone's just pretending to be brave, and none of us really are. Maybe pretending to be brave is how you get brave, I don't know."
- Grenn, A Storm of Swords.
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ratmonky
Famous Hero
Abu Hur Ibn Rashka
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posted November 19, 2004 05:48 PM |
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realdeal, aren't you from denmark? then why didn't you translate it yourself, or did you fear that your Danish isn't good enough?
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Dies illa, dies irae,
Calamitatis et miseriae.
Requiem aeternum
Dona eis, dona eis Domine.
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TheRealDeal
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Foobum* of Justice!
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posted November 20, 2004 02:31 AM |
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My danish is well, but my translation of danish to english in physics terms, might.. well not be
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*We all know the that Foobum is the class of all that is Cake.
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Svarog
Honorable
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statue-loving necrophiliac
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posted November 20, 2004 06:13 AM |
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These are fairly easy problems, but solving someone’s homework was not what I had in mind when I offered my help. If you need help clarifying something, or you don’t understand something in particular, ask me and I will gladly explain it to you. But I wont do your work next time.
I used the standard letters and measurements found in physics. Still, if there’s anything you can’t decipher, feel free to ask.
1. You need the density of glycerol (a threehydroxylic alcohole) here. It should be given in the problem, but if it’s not I assume it’s close to water (1000kg/m^3).
Since d (density)=m/V then V=m/d=(2,5kg)/(1000kg/m^3)= 0,0025m^3 = 2,5 dm^3.
2. Unclear translation. 65 ml of what? I saw in the danish version, it says glycerol, so unless there’s another error in the translation the solution would be:
Q=8,9kJ; V=65ml=0.65dm^3; C and d (of glycerol) should be given
Q (amount of heat) = c (heat capacity)*m*T
T=Q/(c*m)
M=d (density of glycerol)*V
So, T=Q/(c*d*V), then place the exact values, but be careful to place the exact value for the volume - meters cubic or decimeters cubic, which depends on the unit for c.
3. T1=15 C
T2=90 C
M=500g=0.5kg
C (lead) should be given (read from a table)
Q=?
Q=c (lead)*m*(T2-T1)
4. Assuming there are no temperature losses to the environment, we have:
m1=120g=0.12kg; m2=100g=0.1kg; T1=3 C; T2=20 C
Best is if you calculate for each of the “parts of Coke” seperately.
Q=c*m1*(T-T1) (heat transmitted)
Q=c*m2*(T2-T) (heat absorbed)
The heat transmitted is actually the one absorbed by the other part, so:
M1*(T-T1)=m2*(T2-T)
M1*T-m1*T1=m2*T2-m2*T
T(m1+m2)=m1*T1+m2*T2
T=(m1*T1+m2*T2)/(m1+m2)
5. c=3*10^8m/s
t=2.56s
d=?
l=2d (since the laser travels the moon-earth distance twise)
l=c*t
thus, 2d=c*t
d=c*t/2
6. v1=28km/h=28000m/3600s=7.7 m/s
v2=13,5 km/h=13500m/3600s=3.75 m/s
t=6s
a=?
a=(v2-v1)/t
You get a negative value, meaning the acceleration is braking.
7. m=60kg
S=120cm^2=(120/10^4) m^2= 0.012 m^2
P=m/S=60kg/0.012m^2=5000 Pa
8. T=26 C; x=35%; V=1m^3=1000dm^3; m=?
Since atmospheric P is normal, and T is normal (26 C), then the proportion V/n for all gases is 22,4 dm^3/mol.
V/n=22,4dm^3/mol
N=1000dm^3/(22,4 dm^3/mol)=44,6 mol
The x (moisture) given is most probably a molar ratio, so:
n(H2O)=x*N=35%*44,6 mol.=15,6 mol
m(H2O)=Mm(molar mass of H2O)*n(H2O)
Mm=(2*1+16)g/mol=18g/mol
M(H2O)=18g/mol*15,6 mol=279 g (in 1m^3)
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The meek shall inherit the earth, but NOT its mineral rights.
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pandora
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The Chosen One
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posted November 21, 2004 07:20 PM |
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Quote:
These are fairly easy problems, but solving someone’s homework was not what I had in mind when I offered my help. If you need help clarifying something, or you don’t understand something in particular, ask me and I will gladly explain it to you.
Agreed with Svarog here, I think its a great idea for people to share knowledge and help either other out - but getting someone to do your homework? That's no good, you'll get more from your education if you do it yourself.
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"In the end, we will remember not the words of our enemies, but the silence of our friends."
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TheRealDeal
Promising
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Foobum* of Justice!
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posted November 21, 2004 07:24 PM |
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I have done it myself! I'm honest! :S .. i just wanted to know if i'm right... there is a million tests you have to go through, so i'm reading and learning myself. I'm happy to know that people are willing to help.
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*We all know the that Foobum is the class of all that is Cake.
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pandora
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The Chosen One
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posted November 21, 2004 08:01 PM |
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That's good RealDeal, I wasn't posting to scold you or anything lol
I just didn't want to see more people posting their nightly assignments for other HC members to do for them
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"In the end, we will remember not the words of our enemies, but the silence of our friends."
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TheRealDeal
Promising
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Foobum* of Justice!
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posted November 21, 2004 08:02 PM |
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That wasn't my idea at all... I'm really happy that people want to help!
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*We all know the that Foobum is the class of all that is Cake.
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TheRealDeal
Promising
Supreme Hero
Foobum* of Justice!
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posted November 22, 2004 06:55 PM |
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By the way... someone out there that speaks Spanish? .. It would be very nice... I'm working on a translation, and it would be nice if i could post it here when i'm done and then someone could tell me about any possible Grammar Errors.
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*We all know the that Foobum is the class of all that is Cake.
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ratmonky
Famous Hero
Abu Hur Ibn Rashka
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posted November 23, 2004 06:51 PM |
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ok, post it, if it's not too hard for me, i'll help. but don't expect me doing the whole job for you.
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TheRealDeal
Promising
Supreme Hero
Foobum* of Justice!
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posted November 23, 2004 06:59 PM |
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I have given it to my teacher, but now i know that you can help me a bit.
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*We all know the that Foobum is the class of all that is Cake.
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ratmonky
Famous Hero
Abu Hur Ibn Rashka
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posted November 23, 2004 07:07 PM |
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btw, how well do you know spanish? are you a beginner or more an advanced learner? I'm somewhere between intermediate and advanced
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TheRealDeal
Promising
Supreme Hero
Foobum* of Justice!
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posted November 24, 2004 07:10 AM |
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I've had it for about 3-4 months now.. so i'm not advanced
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*We all know the that Foobum is the class of all that is Cake.
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