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Shadowcaster
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Shaded Scribe
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posted October 22, 2003 07:05 AM |
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I took Delfontes's list of numbers and with each successive meter, I added a new number into the mix and the speed at which he broke 500 meters was 255 m/s. It is kind of hard to explain.
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Djive
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Zapper of Toads
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posted October 22, 2003 10:07 PM |
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Edited By: Djive on 22 Oct 2003
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1. 1/2+1/3+1/9 = (9+6+2)/18 = 17/18.
They borrow 1 camel (for total of 18), and then the sons get 9, 6, and 2 camels. Then the borowed camel is returned.
4. We get a series like this for speed. (m/s).
1, 2, 4, 8, 16, 32, 64, 128, 256, 512 and so on...
Now, 2**(500.000) is a number much larger than the speed of light so obviously we need to limit the number, and if nothing else to the speed of light.
Before the speed of light we need to consider the speed of sound, which is about 280 m/s (or 1000km/h) (it's a bit larger but I don't have the exact speed handy.). So dog will hear the sound until he runs faster. The first number larger than 280 m/s is 512 m/s, which means the dog will not accelerate any more once this speed has been attained. (The dog will double his speed at 256 m/s since he can still hear the sound that time around.)
So answer is 512 m/s.
I can actually see a chance for the dog to accelerate also after 512 m/s. Anybody interested in guessing how this could be possible?
5.
100*A + 30*B + 5*C = 1000
A + B + C = 100
This looks to have many solutions, but let's substitute C with 100-A-B in first equation.
100*A + 30*B + 500 - 5A - 5B = 1000
or
95*A + 25*B = 500
We are looking for positive integer solutions to the above equation.
One would be A=0 and B=20 (C=80)
Next one would be A=5 and B=1 (C=94)
There are no further solutions.
Since I assume farmer wants at least one pig ("A" being non-zero), I'd say 5 Pigs (A), 1 Chicken (B) and 94 Chicks (C).
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 22, 2003 10:23 PM |
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So, knowing the speed of sound at sea level was a requirement for that equasion. /shrug
I'd call that a bit cheap, especially considering most dogs don't routinely break the speed of sound anyhow... so why adhere to 1 law of physics and ignore others? 
How many G-forces can a dog withstand anyhow? After going from 32-64 meters per second in 1 second I think it'd kill itself from the extreme exceleration, so maybe it never gets to the other city.
Thanks for the answer Djive, that was annoying me . Now back to anonymoty and mainly H4 related posts for me.
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angelito
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proud father of a princess
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posted October 22, 2003 10:31 PM |
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Congratulations to Djive !!
He solved the last three riddles perfectly.
Yes, the problem was the speed of the sound....when you hear no "bump" anymore, you donīt double your speed anylonger...
Abd the others with the camels and the animals were absolutely perfect explained!
Now I have to search some new AND hard riddles for you, perhaps someone else could post some good riddles in the meantime?
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Djive
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Zapper of Toads
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posted October 22, 2003 10:51 PM |
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Here is my 'impossible' puzzle from an earlier thread (constructed some years ago).
Perhaps, someone will solve it this time around?
Task: Spell out what the equation says.
Equation:
abcde + abd + fgh = ijhdk
Matrix:
IXSF
EWVH
OTNR
Clue #1: The matrix and the equation is connected.
Clue #2: The base for the equation is 12.
Clue #3. Only what is shown in the matrix may appear in the equation.
Clue #4: To solve the equation find three words which associates to the fourth.
(DL 5)
You can ask for a few more clues (though you need to ask for specific things). But be warned that I won't give the answer to this puzzle myself.
____________
"A brilliant light can either illuminate or blind. How will you know which until you open your eyes?"
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Shadowcaster
Honorable
Supreme Hero
Shaded Scribe
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posted October 23, 2003 07:05 AM |
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Here is my semisolution...
NLNLE + NLD + NLH = NLNLK
or
ONQPE + OND + TSH = WVVPK
or
NXPVE + NXD + DFH = VPHVK
That is what I have come up with, and obviously it is wrong, but most of the letters are in this matrix.
IXSF
EWVH
OTNR
I have my calculations written down, but I work in unorthodox ways, so it might be a bit confusing (it confuses me, anyways). I'll try and do more if I am anywhere near the right track.
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noriddler
Tavern Dweller
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posted October 23, 2003 04:24 PM |
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difference between 1.50 and .35 riddle
I am just trying to find the answer.
what is the difference between 1.5 and .35. please explain if the answer is not an obvious one.
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Djive
Honorable
Supreme Hero
Zapper of Toads
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posted October 23, 2003 06:59 PM |
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I can't say if you're on the right track or not, since your reasoning and assumptions made are not included.
It doesn't look too good though. Remember that you can ask for clues... (Though don't expect lengthy or crystal clear answers.  )
____________
"A brilliant light can either illuminate or blind. How will you know which until you open your eyes?"
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IRh
Famous Hero
Lizard
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posted October 23, 2003 07:22 PM |
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To be or not to be, that's the riddle of 100 DL...
May be you are too wise...
My Qs:
1) A boy is going to the jail carrying some food to his father. A girl is going to the hospital carrying flowers for her mother. But they are to cross a road, and cars are going all the time with no enough spaces. What should they (boy and girl) do to get to the prison and the hospital? The traffic lights don't work.
2) A monkey is going to cross the same road. What should it do?
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 23, 2003 07:33 PM |
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Simple, the boy and the girl throw the monkey into the center of traffic.
When the monkey is hit, it will probably cause a pile-up due to the thickness of traffic.
Once all the cars have crashed, and none are left moving, it is safe to cross for the boy and girl.
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IRh
Famous Hero
Lizard
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posted October 23, 2003 07:52 PM |
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NOOOO!
The monkey is alone, unlike the guy&girl. These riddles are not connected. only similar cituations.
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angelito
Honorable
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posted October 23, 2003 08:04 PM |
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Quote:
I am just trying to find the answer.
what is the difference between 1.5 and .35. please explain if the answer is not an obvious one.
Read the riddle carefully and exactly!
....the difference between 1 dollar 50 and 30 5-cents. Got the clue now? There is no difference, both are 1 dollar 50 cents!
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Shadowcaster
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posted October 23, 2003 11:22 PM |
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Well. I came up with three methods, all using malkia's equation in the thread you originally posted this in. For all of the methods, I first substituted 12 for each of the N's and did the subsequent multiplying to satisfy the exponents. I came up with this.
20736a + 1728b + 144c + 12d + e +
144a + 12b + d +
144f + 12g + h =
20736i + 1728j + 144h + 12d + k
After that (which is probably wrong anyways), I became horribly and utterly lost, so I decided to find the remainder of each of the large numbers when divided by 26. I then used each of those remainders to match up with a letter in the alphabet, 1 being a and so on. That is how I reached the top solution.
I then wondered what the letters meant, so I simply added their numberic values to the values set up in part A, each yeilding a new letter relatively close to those in the first solution. The result was the second solution.
The bottom equation also had to do with the numeric values of the letters, yet this time, I decided to multiply that number and the multiple of 12 that it was paired with, then divide that by 26 and take the remainder of those quotients. I assigned those numbers a letter value and came up with the third solution.
Now I am probably doing this problem horribly wrong, as I do not understand how the matrix fits into the equation. I assumed that it was simply an arrangement of letters that were supposed to be included in the solution. Curiously enough, many of my answers were in the matrix. As for a question, what the heck does the matrix have to do with the equation? I'm stumped.
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Djive
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Zapper of Toads
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posted October 24, 2003 12:02 AM |
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Edited By: Djive on 23 Oct 2003
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While Malkia's equation is correct, it's not this equation which should be used to go further. It's much easier and better to set it up as a normal addition and do some trial and error.
If you are trying to add (if you assume Hex numbers) together: 145A6 + 9A23 + 1ACD, then it's rather inefficient to convert the number to decimal, count out the decimal result, and then convert back to hex (and this is basically what you get by using the equation). It's the same in this case.
What you do instead is as follows:
6 + 3 + D = 16
A + 2 + C (+ 1) = 19
5 + A + A (+ 1) = 1A
4 + 9 + 1 (+ 1) = F
1 = 1
For result: 1FA96
(Normally, you would present this vertically instead of horisontally as I've done above.... But this is due to the format of text on the forum is not suitable for the vertical presentation.)
In answer to your question, then this is part of the problem and you need to figure it out.
I'll give you a few cryptic clue/question you should ask yourself.
How many letteres are there in the matrix?
How could this number relate to the information you have about the equation?
____________
"A brilliant light can either illuminate or blind. How will you know which until you open your eyes?"
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angelito
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posted October 24, 2003 12:47 AM |
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Quote:
1) A boy is going to the jail carrying some food to his father. A girl is going to the hospital carrying flowers for her mother. But they are to cross a road, and cars are going all the time with no enough spaces. What should they (boy and girl) do to get to the prison and the hospital? The traffic lights don't work.
Are the boy and the girl standing both on the same side of the road?
If not, they can throw their goodies to the other one and than the girl will go to the jail and the boy to the hospital
Quote:
2) A monkey is going to cross the same road. What should it do?
He has to climb upon the traffic light and jump to the other traffic light across the road
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Shadowcaster
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posted October 24, 2003 01:42 AM |
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Well, there are 12 different letters in the matrix and 11 different letters in the equation. I'm not sure if that is significant, but even if it is, I still have no idea. I only learned that hexadecimal existed six months ago, so much of that equation makes no sense. How does hexadecimal factor in?
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Djive
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posted October 24, 2003 08:42 PM |
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Quote:
How does hexadecimal factor in?
It doesn't, it was just used as an example since the principle of making an addition in it is the same.
Clue #2 gives you the base to use.
The fact that there are 11 digits in Equation and 12 letters in the Matrix, can be used for clue questions. (Though, try to keep them to yes/no questions.)
____________
"A brilliant light can either illuminate or blind. How will you know which until you open your eyes?"
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Shadowcaster
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posted October 25, 2003 12:01 AM |
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Here is a yes or no question that stumps me now that I am finally aware of what a base is: Because 11 different letters are present in the equation and the base is twelve, can we assume that the digits advance much like the alphabet does in relation to the decimal system, going up to L?
____________
>_>
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Djive
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posted October 25, 2003 12:14 AM |
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Edited By: Djive on 25 Oct 2003
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Quote:
Here is a yes or no question that stumps me now that I am finally aware of what a base is: Because 11 different letters are present in the equation and the base is twelve, can we assume that the digits advance much like the alphabet does in relation to the decimal system, going up to L?
Clue: Each letter in equation represents one digit, and always the same digit.
Clue: If all twelve digits were used then I would have used 'l' in the equation.
Answer to Shadowcrusher below: I thought the logic to apply was obvious, and straight forward. (Look at my example.)
____________
"A brilliant light can either illuminate or blind. How will you know which until you open your eyes?"
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Shadowcaster
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posted October 25, 2003 12:54 AM |
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So I'm guessing that some kind of logic will help me to define the values of these digits, am I correct?
____________
>_>
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